CuCl2 = Cu2+ + 2Cl-n(CuCl2) = 27/134=0.2 мольn(Cu) = n(CuCl2) = 2n(Cl) V(Cl) = 0.1*22.4=2.24 лm(Cu) = 64*0.2= 12.8 гр
CuCl2 = Cu2+ + 2Cl-
n(CuCl2) = 27/134=0.2 моль
n(Cu) = n(CuCl2) = 2n(Cl)
V(Cl) = 0.1*22.4=2.24 л
m(Cu) = 64*0.2= 12.8 гр