дано
n(NaOH) = 1.5 mol
m(Na3PO4)-?
3NaOH+H3PO4-->Na3PO4+3H2O
3n(NaOH) = n(Na3PO4)
n(Na3PO4) = 1.5 / 3 = 0.5 mol
M(Na3PO4) = 164 g/mol
m(Na3PO4) = n*M = 0.5 * 164 = 82 g
ответ 82 г
дано
n(NaOH) = 1.5 mol
m(Na3PO4)-?
3NaOH+H3PO4-->Na3PO4+3H2O
3n(NaOH) = n(Na3PO4)
n(Na3PO4) = 1.5 / 3 = 0.5 mol
M(Na3PO4) = 164 g/mol
m(Na3PO4) = n*M = 0.5 * 164 = 82 g
ответ 82 г