n Ar(H)
w =
M(HNO3)
M(HNO3)=63г/моль
w(H)=1/63 =0,02
w(N)=14/63=0.22
w(O)=48/63=0.76
w = (Ar(E)*n/Mr)*100%
w(H)= (1/63)*100% = 1.6 %
w(N) = (14/63)*100% = 22.2 %
w(O) = (16*3/63)*100% = 76.2 %
ответ: 1.6 %, 22.2 %, 76.2 %.
n Ar(H)
w =
M(HNO3)
M(HNO3)=63г/моль
w(H)=1/63 =0,02
w(N)=14/63=0.22
w(O)=48/63=0.76
w = (Ar(E)*n/Mr)*100%
w(H)= (1/63)*100% = 1.6 %
w(N) = (14/63)*100% = 22.2 %
w(O) = (16*3/63)*100% = 76.2 %
ответ: 1.6 %, 22.2 %, 76.2 %.