m(р-ра) = 150 g
m(KOH) = 16.8 g
m(H2SO4) - ?
N(KOH) = 16.8 / 56 = 0.3 mol
0.3 mol x mol
2KOH + H2SO4 = K2SO4 + 2H2O
2 mol 1 mol
2:0.3 = 1:x
2x = 0.3
x = 0.15
m(H2SO4) = 0.15 * 98 = 14.7 g
W(H2SO4) = 14.7 / 150 = 0.098 = 9.8%
m(р-ра) = 150 g
m(KOH) = 16.8 g
m(H2SO4) - ?
N(KOH) = 16.8 / 56 = 0.3 mol
0.3 mol x mol
2KOH + H2SO4 = K2SO4 + 2H2O
2 mol 1 mol
2:0.3 = 1:x
2x = 0.3
x = 0.15
m(H2SO4) = 0.15 * 98 = 14.7 g
W(H2SO4) = 14.7 / 150 = 0.098 = 9.8%