M(KNO3) = 39 + 14 + 48= 101 г/мольw(N) = 14/101*100%= 14%M(NH4NO3) = 14+4+14+48 = 80w(N) = 28/80*100%= 35%
M(KNO3) = 39 + 14 + 48= 101 г/моль
w(N) = 14/101*100%= 14%
M(NH4NO3) = 14+4+14+48 = 80
w(N) = 28/80*100%= 35%