M(CxHy) = 78 g/mol
W(C) = 92.3 %
CxHy - ?
Ar(C) = 0.923 * 78 = 71.994 = 72.
Ar(H) = 78-72=6.
n(C) = 72:12 = 6
n(H) = 6:1 = 6
C6H6
M(CxHy) = 78 g/mol
W(C) = 92.3 %
CxHy - ?
Ar(C) = 0.923 * 78 = 71.994 = 72.
Ar(H) = 78-72=6.
n(C) = 72:12 = 6
n(H) = 6:1 = 6
C6H6