m(NaCl) = 25 g
m(р-ну) = 200 g
W(NaCl 1) = 25%
W(NaCl) - ?
m(NaCl 1) = 0.25 * 200 = 50 g
W(NaCl) = 50+25 / 200 + 25 = 75/225 = 0.333 = 33.3%
m(NaCl) = 25 g
m(р-ну) = 200 g
W(NaCl 1) = 25%
W(NaCl) - ?
m(NaCl 1) = 0.25 * 200 = 50 g
W(NaCl) = 50+25 / 200 + 25 = 75/225 = 0.333 = 33.3%