дано
m(C) = 36 g
V(CH4)-?
C+2H2-->CH4
M(C) = 12 g/mol
n(C) = m/M = 36/12 = 3 mol
n(C) = n(CH4) = 3 mol
V(CH4) = n*Vm = 3*22.4 = 67.2 L
ответ 67.2 л
дано
m(C) = 36 g
V(CH4)-?
C+2H2-->CH4
M(C) = 12 g/mol
n(C) = m/M = 36/12 = 3 mol
n(C) = n(CH4) = 3 mol
V(CH4) = n*Vm = 3*22.4 = 67.2 L
ответ 67.2 л