дано
D(H2) = 35
W(C) = 85.7 % = 0.857
W(H) = 14.3% = 0.143
CxHy-?
M(CxHy) = D(H2) * 2 = 35*2 = 70 g/mol
CxHy / M(CxHy) = W(C) / Ar(C) : W(H) / Ar(H)
CxHy / 70 = 0.857 / 12 : 0.143 / 1
CxHy = 5 : 10
C5H10
ответ С5Н10
дано
D(H2) = 35
W(C) = 85.7 % = 0.857
W(H) = 14.3% = 0.143
CxHy-?
M(CxHy) = D(H2) * 2 = 35*2 = 70 g/mol
CxHy / M(CxHy) = W(C) / Ar(C) : W(H) / Ar(H)
CxHy / 70 = 0.857 / 12 : 0.143 / 1
CxHy = 5 : 10
C5H10
ответ С5Н10