K3[Fe(CN)6]
Объяснение:
M(K)= (329/100)*35.56≈117
n(K)=117/39=3
M(Fe)=(329/100)*17.02≈56
n(Fe)=56/56=1
M(C)=(329/100)*21.88≈72
n(C)=72/12=6
M(N)=329-117-56-72=84
n(N)=84/14=6
K3[Fe(CN)6]
Объяснение:
M(K)= (329/100)*35.56≈117
n(K)=117/39=3
M(Fe)=(329/100)*17.02≈56
n(Fe)=56/56=1
M(C)=(329/100)*21.88≈72
n(C)=72/12=6
M(N)=329-117-56-72=84
n(N)=84/14=6
K3[Fe(CN)6]