дано
m(Al) = 235 g
V(H2) -?
2Al+3H2SO4-->Al2(SO4)3 + 3H2
M(Al) = 27 g/mol
n(Al) = m/M = 235 / 27 = 8.7 mol
2n(Al) = 3n(H2)
n(H2) = 8.7 * 3 / 2 = 13.05 mol
V(H2) = n*Vm = 13.05 * 22.4 = 292.32 L
ответ 292, 32 л
Объяснение:
дано
m(Al) = 235 g
V(H2) -?
2Al+3H2SO4-->Al2(SO4)3 + 3H2
M(Al) = 27 g/mol
n(Al) = m/M = 235 / 27 = 8.7 mol
2n(Al) = 3n(H2)
n(H2) = 8.7 * 3 / 2 = 13.05 mol
V(H2) = n*Vm = 13.05 * 22.4 = 292.32 L
ответ 292, 32 л
Объяснение: