дано
m(CaCO3) = 27 g
V(CO2)-?
Ca(OH)2+CO2-->CaCO3+H2O
M(CaCO3) = 100 g/mol
n(CaCO3) = m/M = 27 / 100 c= 0.27 mol
n(CO2) = n(CaCO3) = 0.27 mol
V(CO2) = n*Vm = 0.27*22.4 = 6.048 L
ответ 6.048 л
дано
m(CaCO3) = 27 g
V(CO2)-?
Ca(OH)2+CO2-->CaCO3+H2O
M(CaCO3) = 100 g/mol
n(CaCO3) = m/M = 27 / 100 c= 0.27 mol
n(CO2) = n(CaCO3) = 0.27 mol
V(CO2) = n*Vm = 0.27*22.4 = 6.048 L
ответ 6.048 л