дано
m(H2S) = 34 g
V(O2) - ?
2H2S+3O2-->2H2O+2SO2
M(H2S) = 34 g/mol
n(H2S) = m/M = 34 / 34 = 1 mol
2n(H2S) = 3n(O2)
n(O2) = 1*3 / 2= 1.5 mol
V(O2) = n*Vm = 1.5 * 22.4 = 33.6 L
ответ 33.6 л
Объяснение:
дано
m(H2S) = 34 g
V(O2) - ?
2H2S+3O2-->2H2O+2SO2
M(H2S) = 34 g/mol
n(H2S) = m/M = 34 / 34 = 1 mol
2n(H2S) = 3n(O2)
n(O2) = 1*3 / 2= 1.5 mol
V(O2) = n*Vm = 1.5 * 22.4 = 33.6 L
ответ 33.6 л
Объяснение: