V(H2) = 5.6 l
n(H2) = V / Vm = 5.6 / 22.4 = 0.25 mol
M(H2) = 2 * 1 = 2 g/mol
m(H2) = M * n = 2 * 0.25 = 0.5 g
V(H2) = 5.6 l
n(H2) = V / Vm = 5.6 / 22.4 = 0.25 mol
M(H2) = 2 * 1 = 2 g/mol
m(H2) = M * n = 2 * 0.25 = 0.5 g
n(ню)(H2)=5,6/22,4=0,25(моль)
m(H2)=n(ню)×М
m(H2)=0,25×2=0,5 (г)
ответ:m(H2)=0,5 г