Решить цепочки по (10 кл.) 1) ch4 > x1 , > x2 , > x3 , > x4 2) ch3-ch2-ch(ch3)-ch3 , > x1 , > x2 > x3 > x4 > co2

1)
2CH4 = CH=-CH + 3H2
(CH=-CH)3 = C6H6 
C6H6 + CH3Cl = C6H5CH3 + HCl
5C6H5CH3 + 6KMnO4 + 9H2SO4 = 5C6H5COOH + 3K2SO4 + 6MnSO4 + 14H2O

2)
CH3-CH2-CH(CH3)-CH3 + Br2 = CH3-CH2-C(Br)(CH3)-CH3 + HBr
CH3-CH2-C(Br)(CH3)-CH3 + KOH = CH3-CH=C(CH3)-CH3 + KBr + H2O 
CH3-CH=C(CH3)-CH3 + HBr = CH3-CH2-C(Br)(CH3)-CH3 
Если дальше Na, то хз, если NaOH водн, то: 
CH3-CH2-C(OH)(CH3)-CH3 + NaBr 
CH3-CH2-C(OH)(CH3)-CH3 + 7,5O2 = 6H2O + 5CO2