1) Ba + 2HCl = BaCl2 + H2
13.7/137 = x/22.4
x = 2.24 л
2) 2Na + H2SO4 = Na2SO4 + H2
49/98 = y/142
y = 71 г
1) Ba + 2HCl = BaCl2 + H2
13.7/137 = x/22.4
x = 2.24 л
2) 2Na + H2SO4 = Na2SO4 + H2
49/98 = y/142
y = 71 г