1) pH=-lg(0.001)=3
2) [H+]=(10^-14)/(0.002)=5*10^(-12)
pH=-lg(5*10^(-12))=11.3
3)[H+]=(0.1*6.3*10^-5)^1/2=0,0025
pH=-lg(0,0025)=2.6
1) pH=-lg(0.001)=3
2) [H+]=(10^-14)/(0.002)=5*10^(-12)
pH=-lg(5*10^(-12))=11.3
3)[H+]=(0.1*6.3*10^-5)^1/2=0,0025
pH=-lg(0,0025)=2.6