BaCl2 + H2SO4 = BaSO4 + 2HCl
1) 0.049= x / 200
x = 9.8
m(H2SO4)= 9.8 г
2) n(H2SO4)= 9.8/98=0.1 моль
n(BaSO4) = 0.1 моль
3) m(BaSO4) = 0.1 *233= 23.3 г
BaCl2 + H2SO4 = BaSO4 + 2HCl
1) 0.049= x / 200
x = 9.8
m(H2SO4)= 9.8 г
2) n(H2SO4)= 9.8/98=0.1 моль
n(BaSO4) = 0.1 моль
3) m(BaSO4) = 0.1 *233= 23.3 г