Дано
m(KCl) = 40 г
Решение
Mr(KCl) = Ar(K) + Ar(Cl) = 39 + 35.5 = 74.5
w(K) = Ar(K) / Mr(KCl) = 39 / 74.5 = 0.5235 = 52.35%
m(K) = m(KCl)w(KCl) = 40 * 0.5235 = 20.94 г
w(K) = 52.35%
m(K) = 20.94 г
Дано
m(KCl) = 40 г
Решение
Mr(KCl) = Ar(K) + Ar(Cl) = 39 + 35.5 = 74.5
w(K) = Ar(K) / Mr(KCl) = 39 / 74.5 = 0.5235 = 52.35%
m(K) = m(KCl)w(KCl) = 40 * 0.5235 = 20.94 г
w(K) = 52.35%
m(K) = 20.94 г