2HCl+Zn--->ZnCl2+H2
n(H2)=67,2l/22,4l/mol=3mol
n(ZnCl2)=3mol
M(ZnCl2)=65+35,5*2=136g/mol
m(ZnCl2)=3mol*136g/mol=408g
2HCl+Zn--->ZnCl2+H2
n(H2)=67,2l/22,4l/mol=3mol
n(ZnCl2)=3mol
M(ZnCl2)=65+35,5*2=136g/mol
m(ZnCl2)=3mol*136g/mol=408g