CaCO3+2HCl=>CaCl2+CO2+H2O
xг(CaCO3)3,38л(CO2)
100г(CaCO3)22,4л(CO2)
х=(3,38*100)/22,4=15,09л CaCO3
28,8г100%.
15,09лх
х=(15,09*100)/28,8=52,4%
ответ:52,4%
CaCO3+2HCl=>CaCl2+CO2+H2O
xг(CaCO3)3,38л(CO2)
100г(CaCO3)22,4л(CO2)
х=(3,38*100)/22,4=15,09л CaCO3
28,8г100%.
15,09лх
х=(15,09*100)/28,8=52,4%
ответ:52,4%