CxHy + O2 = x CO2 + y/2 H2O M(CxHy) = 2.69*28 = 75 г/моль n(CxHy) = 7.8/75 = 0.1 моль n(CO2) = 26.4/44 = 0.6 моль n(H2O) = 5.4/18 = 0.3 моль x = 1*0.6/0.1 = 6 y/2 = 1*0.3/0.1: y = 6 ответ С6Н6
CxHy + O2 = x CO2 + y/2 H2O
M(CxHy) = 2.69*28 = 75 г/моль
n(CxHy) = 7.8/75 = 0.1 моль
n(CO2) = 26.4/44 = 0.6 моль
n(H2O) = 5.4/18 = 0.3 моль
x = 1*0.6/0.1 = 6
y/2 = 1*0.3/0.1: y = 6
ответ С6Н6