M(CaCO3) = 40+12+16*3 = 100 g/mol
W(Ca) = 40/100*100% = 40%
W(C) = 12/100*100% = 12 %
W(O) = 16*3 / 100*100% = 48%
M(CaCO3) = 40+12+16*3 = 100 g/mol
W(Ca) = 40/100*100% = 40%
W(C) = 12/100*100% = 12 %
W(O) = 16*3 / 100*100% = 48%