m(BaO) = 3075.3 g
m(соли) - ?
Ф-ла соли - ?
n(BaO) = 3075.3 / 153 = 20.1 mol
20.1 mol x mol
BaO + H2SO4 = BaSO4 + H2O
1 mol 1 mol
1:20.1 = 1:x
x = 20.1
m(BaSO4) = 20.1 * 233 = 4683.3 g
ответ: BaSO4 , 4683.3 g .
m(BaO) = 3075.3 g
m(соли) - ?
Ф-ла соли - ?
n(BaO) = 3075.3 / 153 = 20.1 mol
20.1 mol x mol
BaO + H2SO4 = BaSO4 + H2O
1 mol 1 mol
1:20.1 = 1:x
x = 20.1
m(BaSO4) = 20.1 * 233 = 4683.3 g
ответ: BaSO4 , 4683.3 g .