Определить массовую долю раствора, если к200 грамм 6% раствора добавили 12 граммов соли
Гелик2132
2
18.10.2021 23:55
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2
11,3%
Объяснение:
m (соли исх) = 200*0,06 =12г
m (соли) = 12 +12 =24г
m (р-ра) =200+12 =212 г
ω = (24/212)* 100%