so3+h20=h2s04
h2so4+2koh=k2so4+2h2o
n(so3)=16/80=0.2 mol
n(k2so4)=0.2 mol
m(k2so4)=0.2*174=34.8
ответ:34.8 г
so3+h20=h2s04
h2so4+2koh=k2so4+2h2o
n(so3)=16/80=0.2 mol
n(k2so4)=0.2 mol
m(k2so4)=0.2*174=34.8
ответ:34.8 г