V(CH4) = 4 l
V(H2) - ?
n(CH4) = 4 / 22.4 = 0.178 mol = 0.18 mol
x mol 0.18 mol
2H2 + C = CH4
2 mol 1 mol
2:x = 1:0.18
x = 0.36
V(H2) = 0.36 * 22.4 = 8.064 l
ответ: 8.064 l .
V(CH4) = 4 l
V(H2) - ?
n(CH4) = 4 / 22.4 = 0.178 mol = 0.18 mol
x mol 0.18 mol
2H2 + C = CH4
2 mol 1 mol
2:x = 1:0.18
x = 0.36
V(H2) = 0.36 * 22.4 = 8.064 l
ответ: 8.064 l .