m(Fe)=400*0.92=368г
2Fe2O3+3C=3CO2+4Fe
n(Fe)=368/56=6.57моль
n(C)=6.57*3/2=4.381моль
m(C)=4.381*12=52.57г
m(Fe)=400*0.92=368г
2Fe2O3+3C=3CO2+4Fe
n(Fe)=368/56=6.57моль
n(C)=6.57*3/2=4.381моль
m(C)=4.381*12=52.57г