Ba+2H2O=Ba(OH)2+H2
1 1 1
n(Ba)=82,2/137=0,6; n(Ba(OH)2)=0,6; m(BA(OH)2)=0,6*171=102,6;
n(H2)=0,6; m(H2)=0,6*2=1,2; m(р-ра) =500+82,2-1,2=581;
W(Ba(OH)2)=102,6/581=0,1766(17,66%).
Ba+2H2O=Ba(OH)2+H2
1 1 1
n(Ba)=82,2/137=0,6; n(Ba(OH)2)=0,6; m(BA(OH)2)=0,6*171=102,6;
n(H2)=0,6; m(H2)=0,6*2=1,2; m(р-ра) =500+82,2-1,2=581;
W(Ba(OH)2)=102,6/581=0,1766(17,66%).