НУЖНА ! 2Fe+3Cl2=2FeCl3
1.) Определите какой объём Cl2 вступит в реакцию с 5,6г железа
2.) Для сжигания железа взяли 6,72л хлора. Определите массу образов FeCl3
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17.02.2022 16:50
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0,1. х
2Fe+3Cl2-->2FeCl3
х=0,1×3:2=0,15
n(Fe)=5,6:56=0,1
V(Cl2)=0,15×22,4=3,36л
0,3. 0,2
2Fe+3Cl2-->2FeCl3
х=0,3×2:3=0,2
n(Cl)=6,72:22,4=0,3
m(FeCl3)=0,3×162=48,2г