дано
W(C) = 91.3%= 0.913
D(CH4) = 5.75
CxHy-?
W(H) = 1 - 0.913 = 0.087
M(CxHy)= D(CH4) * 5.75 = 16*5.75= 92 g/mol
CxHy / 92 = 0.913 / 12 : 0.087 / 1
CxHy = 7:8
C7H8
ответ КЛАСС - АРЕНЫ (C6H5 - CH3)
дано
W(C) = 91.3%= 0.913
D(CH4) = 5.75
CxHy-?
W(H) = 1 - 0.913 = 0.087
M(CxHy)= D(CH4) * 5.75 = 16*5.75= 92 g/mol
CxHy / 92 = 0.913 / 12 : 0.087 / 1
CxHy = 7:8
C7H8
ответ КЛАСС - АРЕНЫ (C6H5 - CH3)