дано
p(HCL) = 1.078 g/ml
W(HCL) = 16%
V(H2) = 4 L
V(ppaHCL)-?
2HCL-->H2+CL2
n(H2) = V(H2) / Vm = 4/22.4 = 0.18 mol
2n(HCL) = n(H2)
n(HCL) =2*0.18 = 0.36 mol
M(HCL) = 36.5 g/mol
m(HCL) = n*M = 0.36 * 36.5 = 13.14 g
m(ppa 16% HCL) = 13.14 * 100% / 16% = 82.125 g
V(ppa HCL) = m(ppa 16% HCL ) / p(HCL) = 82.15 / 1.078 = 76.18 мл
ответ 76.18 мл
дано
p(HCL) = 1.078 g/ml
W(HCL) = 16%
V(H2) = 4 L
V(ppaHCL)-?
2HCL-->H2+CL2
n(H2) = V(H2) / Vm = 4/22.4 = 0.18 mol
2n(HCL) = n(H2)
n(HCL) =2*0.18 = 0.36 mol
M(HCL) = 36.5 g/mol
m(HCL) = n*M = 0.36 * 36.5 = 13.14 g
m(ppa 16% HCL) = 13.14 * 100% / 16% = 82.125 g
V(ppa HCL) = m(ppa 16% HCL ) / p(HCL) = 82.15 / 1.078 = 76.18 мл
ответ 76.18 мл