2Na+2H2O=2NaOH+H2
v(Na)=2.3/23=0.1
=> v(NaOH)/2=v(H2)=>
m(H2)=0.1x1/2=0.05г
V(H2)=22.4x0.1/2=1.12л
m(NaOH)=0.1x40=4г
2Na+2H2O=2NaOH+H2
v(Na)=2.3/23=0.1
=> v(NaOH)/2=v(H2)=>
m(H2)=0.1x1/2=0.05г
V(H2)=22.4x0.1/2=1.12л
m(NaOH)=0.1x40=4г