n(NaOH) = 50/40 = 1,25моль
c(NaOH) = 1,25/10 =0,125моль/л
[OH-] = 0,125моль/л
pOH = -lg[OH-]
pOH =0,9
pH = 14-pOH =14-0.9 = 13,1
pH = -lg[H+]
[H+] = 7,9*10^(-14)
n(NaOH) = 50/40 = 1,25моль
c(NaOH) = 1,25/10 =0,125моль/л
[OH-] = 0,125моль/л
pOH = -lg[OH-]
pOH =0,9
pH = 14-pOH =14-0.9 = 13,1
pH = -lg[H+]
[H+] = 7,9*10^(-14)