дано
m(C6H6) = 32.5 g
V(O2)-?
2C6H6+15O2-->12CO2+6H2O
M(C6H6) = 78 g/mol
n(C6H6) = m/M = 32.5 / 78 = 0.42 mol
2n(C6H6) = 15n(O2)
n(O2) = 0.42 * 15 / 2 = 3.15 mol
V(O2) = n*Vm = 3.15 * 22.4 = 70.56 L
ответ 70.56 л
Объяснение:
дано
m(C6H6) = 32.5 g
V(O2)-?
2C6H6+15O2-->12CO2+6H2O
M(C6H6) = 78 g/mol
n(C6H6) = m/M = 32.5 / 78 = 0.42 mol
2n(C6H6) = 15n(O2)
n(O2) = 0.42 * 15 / 2 = 3.15 mol
V(O2) = n*Vm = 3.15 * 22.4 = 70.56 L
ответ 70.56 л
Объяснение: