16 литров
2(HNO3)+Al=Al(NO3)2+H2
m(HNO3)=600*0.15=90g
M(HNO3)=1+14+16*3=63g/mol
90/126=x/22.4
126x=2016
x=16 литров
16 литров
2(HNO3)+Al=Al(NO3)2+H2
m(HNO3)=600*0.15=90g
M(HNO3)=1+14+16*3=63g/mol
90/126=x/22.4
126x=2016
x=16 литров