Какая масса 10% раствора фосфорной кислоты потребуется для взаимодействия с раствором, содержащим 33,6 г гидроксида k
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20.05.2019 14:50
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2
3KOH+H3PO4=K3PO4+3H2O
n(KOH)=33,6/56=0,6 моль
n(H3PO4)=1/3n(KOH)=0,6/3=0,2 моль
m(H3PO4)=0,2*98=19,6 г
Учитывая что необходим р-р
m(р-ра H3PO4)=19,6/0,1=196 г