дано
m(ppa CuCL2) = 27 g
W(CuCL2) = 10%
+Na2S
m(CuS)-?
m(CuCL2) = 27*10% / 100% = 2.7 g
CuCL2+Na2S-->CuS↓+2NaCL
M(CuCL2) = 135 g/mol
n(CuCL2) = m/M = 2.7 / 135 = 0.02 mol
n(CuS) = n(CuCL2) = 0.02 mol
M(CuS) = 96 g/mol
m(CuS) = n*M = 0.02*96 = 1.92 g
ответ 1.92 г
дано
m(ppa CuCL2) = 27 g
W(CuCL2) = 10%
+Na2S
m(CuS)-?
m(CuCL2) = 27*10% / 100% = 2.7 g
CuCL2+Na2S-->CuS↓+2NaCL
M(CuCL2) = 135 g/mol
n(CuCL2) = m/M = 2.7 / 135 = 0.02 mol
n(CuS) = n(CuCL2) = 0.02 mol
M(CuS) = 96 g/mol
m(CuS) = n*M = 0.02*96 = 1.92 g
ответ 1.92 г