Reply by Kolokokosik
NaOH + HCl = NaCl + H2O
n(NaOH) = m/M = 20/40 = 0.5моль
n(NaCl) = 0.5 моль, m(NaCl) = M*n = 58.5*0.5 = 29.25 г - масса соли
Reply by Kolokokosik
NaOH + HCl = NaCl + H2O
n(NaOH) = m/M = 20/40 = 0.5моль
n(NaCl) = 0.5 моль, m(NaCl) = M*n = 58.5*0.5 = 29.25 г - масса соли