дано
m(ppa NaOH) = 200 g
W(NaOH) = 10%
+H2S
V(H2S)-?
m(NaOH) = 200 * 10% /100% = 20 g
2NaOH+H2S-->Na2S+H2O
M(NaOH) = 40 g/mol
n(NaOH) = m/M = 20 / 40 = 0.5mol
2n(NaOH) = n(H2S)
n(H2S) = 0.5 / 2 = 0.25 mol
V(H2S) = n*Vm = 0.25 *22.4 = 5.6 L
ответ 5.6 л
дано
m(ppa NaOH) = 200 g
W(NaOH) = 10%
+H2S
V(H2S)-?
m(NaOH) = 200 * 10% /100% = 20 g
2NaOH+H2S-->Na2S+H2O
M(NaOH) = 40 g/mol
n(NaOH) = m/M = 20 / 40 = 0.5mol
2n(NaOH) = n(H2S)
n(H2S) = 0.5 / 2 = 0.25 mol
V(H2S) = n*Vm = 0.25 *22.4 = 5.6 L
ответ 5.6 л