1) 2NH4Cl+Ca(OH)2=2NH3+CaCl2+2H2O
m(NH3)=53.5/(2*M(NH4Cl))*2*M(NH3)=53.5/(2*53.5)*2*17=17 г
2) N2+3H2=2NH3
v(NH3)=V(N2)/(2*22.4)*22.4=1/2*44.8=22.4 л
1) 2NH4Cl+Ca(OH)2=2NH3+CaCl2+2H2O
m(NH3)=53.5/(2*M(NH4Cl))*2*M(NH3)=53.5/(2*53.5)*2*17=17 г
2) N2+3H2=2NH3
v(NH3)=V(N2)/(2*22.4)*22.4=1/2*44.8=22.4 л