33.69°
Объяснение:
normal equation of a straight line is y=kx+b
k - is slope of a straight line
2x-3y+1=0
3y=2x+1
y=(2x+1) : 3
y=
if A is angle of inclination of a straight line then
k=tg(A)
tg(A) =
A=33.6900675259798°
33.69°
Объяснение:
normal equation of a straight line is y=kx+b
k - is slope of a straight line
2x-3y+1=0
3y=2x+1
y=(2x+1) : 3
y=
if A is angle of inclination of a straight line then
k=tg(A)
tg(A) =
A=33.6900675259798°