I AB I = √(4-12)²+(8-11)²=√64+9=√73
I BC I = √(12-7)²+(11-0)²=√25+121=√146
I AC I =√(4-7)²+(8-0)²=√9+64=√73 ⇒ AB=BC, но AB≠BC и BC≠AC
I AB I = √(4-12)²+(8-11)²=√64+9=√73
I BC I = √(12-7)²+(11-0)²=√25+121=√146
I AC I =√(4-7)²+(8-0)²=√9+64=√73 ⇒ AB=BC, но AB≠BC и BC≠AC