Вжелезном проводнике сечением 0,5мм2 при напряжении 20в сила тока 1а.какова длина проводника?
UzZzeR
3
20.07.2019 00:00
1
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3
R=U/I= 20В / 1А= 20 Ом
R=p*L/S
L=R*S/p= 20 Ом * 0,5*10^-6м^2 / 10^-7 = 100 м