Тепловоз тэ3 при скорости 21,6км/ч развивает силу тяги 461кн. какая работа совершается течении 1 часа а
darivorobey
2
01.06.2019 18:50
3 
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найдём работу по формуле A = FS cosa = FS = 461000*21600 = 9957.6 МДж.