Температура латунной детали массой 0,2 килограмм ровна 365 градусов по цельсию какое количество теплоты она передаст окружающим телам если ее охладить на 15градусов
TemhenkoShasa
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07.08.2019 20:40
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2
t1=365°C. |Q=0,2•400•(15-365)= -28000 Дж= -28 кДж
t2=15°C. |
c=400 Дж/кг•°C|
|
Q-?
ответ:Латунная деталь передаст окружающим телам -28кДж.