сделать тест по физике ( с формулами к каждому номеру)

1)При выполнении лабораторной работы по определению коэффициента полезного действия установки, состоящей из подвижного и неподвижного блоков, груз массой m = 400 г был поднят равномерно на высоту h = 0,5 м силой F = 2,5 Н . Каков вес поднимаемого груза? Вычислите полезную работу.Вычислите полную работу.Каков КПД блоков?
2)Накачивая воду насосом, к рукоятке прилагают силу 15 Н и при одном движении перемещают ее на расстояние H = 40 см (рис. 84). Поршень насоса оказывает сопротивление 50 Н и поднимается на высоту h =10 см. Вычислите КПД насоса нужны только формулы , но лучше с решением

1) The weight of an object can be calculated using the formula:

Weight = mass * gravitational acceleration

Given that the mass of the object is 400 grams, or 0.4 kilograms, and the gravitational acceleration is approximately 9.8 m/s^2, we can substitute these values into the formula:

Weight = 0.4 kg * 9.8 m/s^2 = 3.92 N

Therefore, the weight of the lifted object is approximately 3.92 Newtons.

To calculate the useful work done, we can use the formula:

Useful Work = force * distance

Given that the force applied is 2.5 Newtons and the distance moved is 0.5 meters, we can substitute these values into the formula:

Useful Work = 2.5 N * 0.5 m = 1.25 Joules

Therefore, the useful work done is approximately 1.25 Joules.

To calculate the total work done, we can use the same formula:

Total Work = force * distance

However, in this case, the force applied is equal to the weight of the object, which we calculated to be 3.92 Newtons. The distance moved is still 0.5 meters, so we substitute these values into the formula:

Total Work = 3.92 N * 0.5 m = 1.96 Joules

Therefore, the total work done is approximately 1.96 Joules.

The efficiency or coefficient of performance (COP) can be calculated using the formula:

COP = (Useful Work / Total Work) * 100%

Substituting the previously calculated values:

COP = (1.25 J / 1.96 J) * 100% = 63.77%

Therefore, the coefficient of performance of the system is approximately 63.77%.

2) To calculate the efficiency of the pump, we first need to find the work done by the applied force and the work done against the resistance of the piston.

The work done by the applied force can be calculated using the formula:

Work = force * distance

Given that the force applied is 15 Newtons and the distance moved is 40 cm, or 0.4 meters, we can substitute these values into the formula:

Work = 15 N * 0.4 m = 6 Joules

Therefore, the work done by the applied force is 6 Joules.

The work done against the resistance of the piston can be calculated using the same formula:

Work = force * distance

Given that the force resisting the piston is 50 Newtons and the distance moved is 10 cm, or 0.1 meters, we can substitute these values into the formula:

Work = 50 N * 0.1 m = 5 Joules

Therefore, the work done against the resistance of the piston is 5 Joules.

To calculate the efficiency or coefficient of performance (COP) of the pump, we can use the formula:

COP = (Useful Work / Total Work) * 100%

In this case, the useful work is the work done by the applied force, which is 6 Joules, and the total work is the sum of the work done by the applied force and the work done against the resistance:

Total Work = 6 J + 5 J = 11 Joules

Substituting these values into the formula:

COP = (6 J / 11 J) * 100% = 54.55%

Therefore, the coefficient of performance of the pump is approximately 54.55%.

I hope this explanation helps you understand the physics concepts and calculations involved in solving these questions!