Рабочий массой 80 кг держит на плечах алюминиевую деталь объёмом 0,01 м в кубе.с какой силой он действует на пол? g принять равной 10 н\кг.плотность алюминия 2700 кг\м в кубе
умник1622
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08.06.2019 12:10
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1
2)m=
3)F=mg=10 Н/кг*107кг=1070 Н