Движения двух тел по шоссе заданы уравнениями: х1 = 100t + 2t^2 и х2 = 18 +100t. Указать координату встречи?
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13.07.2020 22:58
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Объяснение:
x₁ = 100·t + 2·t²
x₂ = 18 + 100·t
1)
Тела встретились, значит:
x₁ = x₂
100·t + 2·t² = 18 + 100·t
2·t² = 18
t² = 9
t = 3 с - время встречи
x₂ = 18 + 100·t = 18 + 100·3 = 318 м - место встречи.