18.1. Вес первого груза (см. ри-
сунок) 20 Н. Каков вес
второго груза?
дошикестдошик
3
28.04.2020 14:25
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2
l1 = 4x
l2 = 2x
Р1 = 20 Н
Найти: Р2 - ?
Пусть х - одно деление рычага, тогда l1 = 4x, l2 = 2x
Рычаг находится в равновесии
=> l1/l2 = P2/P1
P2 = (l1 × P1)/l2
P2 = (4х × 20 Н)/2х = (4 × 20 Н)/2 = 80 Н/2 = 40 Н
Объяснение: как-то так, не 1-й раз это решаю ;)
где рисунок